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- /*-
- * SPDX-License-Identifier: BSD-2-Clause
- *
- * Copyright (c) 2003 Poul-Henning Kamp
- * All rights reserved.
- *
- * Redistribution and use in source and binary forms, with or without
- * modification, are permitted provided that the following conditions
- * are met:
- * 1. Redistributions of source code must retain the above copyright
- * notice, this list of conditions and the following disclaimer.
- * 2. Redistributions in binary form must reproduce the above copyright
- * notice, this list of conditions and the following disclaimer in the
- * documentation and/or other materials provided with the distribution.
- *
- * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
- * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
- * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
- * ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
- * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
- * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
- * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
- * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
- * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
- * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
- * SUCH DAMAGE.
- */
- #include <sys/types.h>
- #include <err.h>
- #include <md5.h>
- #include <stdio.h>
- #include <string.h>
- #include <unistd.h>
- #include "crypt.h"
- /*
- * UNIX password
- */
- int
- crypt_md5(const char *pw, const char *salt, char *buffer)
- {
- MD5_CTX ctx,ctx1;
- unsigned long l;
- int sl, pl;
- u_int i;
- u_char final[MD5_SIZE];
- const char *ep;
- static const char *magic = "$1$";
- /* If the salt starts with the magic string, skip that. */
- if (!strncmp(salt, magic, strlen(magic)))
- salt += strlen(magic);
- /* It stops at the first '$', max 8 chars */
- for (ep = salt; *ep && *ep != '$' && ep < salt + 8; ep++)
- continue;
- /* get the length of the true salt */
- sl = ep - salt;
- MD5Init(&ctx);
- /* The password first, since that is what is most unknown */
- MD5Update(&ctx, (const u_char *)pw, strlen(pw));
- /* Then our magic string */
- MD5Update(&ctx, (const u_char *)magic, strlen(magic));
- /* Then the raw salt */
- MD5Update(&ctx, (const u_char *)salt, (u_int)sl);
- /* Then just as many characters of the MD5(pw,salt,pw) */
- MD5Init(&ctx1);
- MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
- MD5Update(&ctx1, (const u_char *)salt, (u_int)sl);
- MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
- MD5Final(final, &ctx1);
- for(pl = (int)strlen(pw); pl > 0; pl -= MD5_SIZE)
- MD5Update(&ctx, (const u_char *)final,
- (u_int)(pl > MD5_SIZE ? MD5_SIZE : pl));
- /* Don't leave anything around in vm they could use. */
- memset(final, 0, sizeof(final));
- /* Then something really weird... */
- for (i = strlen(pw); i; i >>= 1)
- if(i & 1)
- MD5Update(&ctx, (const u_char *)final, 1);
- else
- MD5Update(&ctx, (const u_char *)pw, 1);
- /* Now make the output string */
- buffer = stpcpy(buffer, magic);
- buffer = stpncpy(buffer, salt, (u_int)sl);
- *buffer++ = '$';
- MD5Final(final, &ctx);
- /*
- * and now, just to make sure things don't run too fast
- * On a 60 Mhz Pentium this takes 34 msec, so you would
- * need 30 seconds to build a 1000 entry dictionary...
- */
- for(i = 0; i < 1000; i++) {
- MD5Init(&ctx1);
- if(i & 1)
- MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
- else
- MD5Update(&ctx1, (const u_char *)final, MD5_SIZE);
- if(i % 3)
- MD5Update(&ctx1, (const u_char *)salt, (u_int)sl);
- if(i % 7)
- MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
- if(i & 1)
- MD5Update(&ctx1, (const u_char *)final, MD5_SIZE);
- else
- MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
- MD5Final(final, &ctx1);
- }
- l = (final[ 0]<<16) | (final[ 6]<<8) | final[12];
- _crypt_to64(buffer, l, 4); buffer += 4;
- l = (final[ 1]<<16) | (final[ 7]<<8) | final[13];
- _crypt_to64(buffer, l, 4); buffer += 4;
- l = (final[ 2]<<16) | (final[ 8]<<8) | final[14];
- _crypt_to64(buffer, l, 4); buffer += 4;
- l = (final[ 3]<<16) | (final[ 9]<<8) | final[15];
- _crypt_to64(buffer, l, 4); buffer += 4;
- l = (final[ 4]<<16) | (final[10]<<8) | final[ 5];
- _crypt_to64(buffer, l, 4); buffer += 4;
- l = final[11];
- _crypt_to64(buffer, l, 2); buffer += 2;
- *buffer = '\0';
- /* Don't leave anything around in vm they could use. */
- memset(final, 0, sizeof(final));
- return (0);
- }
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