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- % Examples of use of Groebner code.
- % In the Examples 1 - 3 the polynomial ring for the ideal operations
- % (variable sequence, term order mode) is defined globally in advance.
- % Example 1, Linz 85.
- torder ({q1,q2,q3,q4,q5,q6},lex)$
- groebner {q1,
- q2**2 + q3**2 + q4**2,
- q4*q3*q2,
- q3**2*q2**2 + q4**2*q2**2 + q4**2*q3**2,
- q6**2 + 1/3*q5**2,
- q6**3 - q5**2*q6,
- 2*q2**2*q6 - q3**2*q6 - q4**2*q6 + q3**2*q5 - q4**2*q5,
- 2*q2**2*q6**2 - q3**2*q6**2 - q4**2*q6**2 - 2*q3**2*q5*q6
- + 2*q4**2*q5*q6 - 2/3*q2**2*q5**2 + 1/3*q3**2*q5**2
- + 1/3*q4**2*q5**2,
- - q3**2*q2**2*q6 - q4**2*q2**2*q6 + 2*q4**2*q3**2*q6 -
- q3**2*q2**2*q5 + q4**2*q2**2*q5,
- - q3**2*q2**2*q6**2 - q4**2*q2**2*q6**2 + 2*q4**2*q3**2*q6**2
- + 2*q3**2*q2**2*q5*q6 - 2*q4**2*q2**2*q5*q6 + 1/3*q3**2*q2**2
- *q5**2 + 1/3*q4**2*q2**2*q5**2 - 2/3*q4**2*q3**2*q5**2,
- - 3*q3**2*q2**4*q5*q6**2 + 3*q4**2*q2**4*q5*q6**2
- + 3*q3**4*q2**2*q5*q6**2 - 3*q4**4*q2**2*q5*q6**2
- - 3*q4**2*q3**4*q5*q6**2 + 3*q4**4*q3**2*q5*q6**2
- + 1/3*q3**2*q2**4*q5**3 - 1/3*q4**2*q2**4*q5**3
- - 1/3*q3**4*q2**2*q5**3 + 1/3*q4**4*q2**2*q5**3 + 1/3*q4**2
- *q3**4*q5**3 - 1/3*q4**4*q3**2*q5**3};
- % Example 2. (Little) Trinks problem with 7 polynomials in 6 variables.
- trinkspolys:={45*p + 35*s - 165*b - 36,
- 35*p + 40*z + 25*t - 27*s,
- 15*w + 25*p*s + 30*z - 18*t - 165*b**2,
- - 9*w + 15*p*t + 20*z*s,
- w*p + 2*z*t - 11*b**3,
- 99*w - 11*s*b + 3*b**2,
- b**2 + 33/50*b + 2673/10000}$
- trinksvars := {w,p,z,t,s,b}$
- torder(trinksvars,lex)$
- switch varopt; off varopt;
- groebner trinkspolys;
- groesolve ws;
-
- % Example 3. Hairer, Runge-Kutta 1, 6 polynomials 8 variables.
-
- torder({c2,c3,b3,b2,b1,a21,a32,a31},lex);
- groebnerf{c2 - a21,
- c3 - a31 - a32,
- b1 + b2 + b3 - 1,
- b2*c2 + b3*c3 - 1/2,
- b2*c2**2 + b3*c3**2 - 1/3,
- b3*a32*c2 - 1/6};
-
-
- % The examples 4 and 5 use automatic variable extraction.
- % Example 4.
-
- torder gradlex$
-
- g4:=
- groebner{b + e + f - 1,
- c + d + 2*e - 3,
- b + d + 2*f - 1,
- a - b - c - d - e - f,
- d*e*a**2 - 1569/31250*b*c**3,
- c*f - 587/15625*b*d};
- hilbertpolynomial g4;
- glexconvert(g4,gvarslast,newvars={e},maxdeg=8);
- % Example 5.
- off varopt;
- torder({u0,u2,u3,u1},lex)$
- groesolve({u0**2 - u0 + 2*u1**2 + 2*u2**2 + 2*u3**2,
- 2*u0*u1 + 2*u1*u2 + 2*u2*u3 - u1,
- 2*u0*u2 + u1**2 + 2*u1*u3 - u2,
- u0 + 2*u1 + 2*u2 + 2*u3 - 1},
- {u0,u2,u3,u1});
-
- % Example 6. (Big) Trinks problem with 6 polynomials in 6 variables.
-
- torder(trinksvars,lex)$
- btbas:=
- groebner{45*p + 35*s - 165*b - 36,
- 35*p + 40*z + 25*t - 27*s,
- 15*w + 25*p*s + 30*z - 18*t - 165*b**2,
- -9*w + 15*p*t + 20*z*s,
- w*p + 2*z*t - 11*b**3,
- 99*w - 11*b*s + 3*b**2};
-
- % The above system has dimension zero. Therefore its Hilbert polynomial
- % is a constant which is the number of zero points (including complex
- % zeros and multipliticities);
- hilbertpolynomial ws;
- % Example of Groebner with numerical postprocessing.
- on rounded;off varopt;
- groesolve(trinkspolys,trinksvars);
- off rounded;
- % Additional groebner operators.
- % Reduce one polynomial wrt the basis of big Trinks. The result 0
- % is a proof for the ideal membership of the polynomial.
- torder(trinksvars,lex)$
- preduce(45*p + 35*s - 165*b - 36,btbas);
-
- % The following examples show how to work with the distributive
- % form of polynomials.
- torder({u0,u1,u2,u3},gradlex)$
- gsplit(2*u0*u2 + u1**2 + 2*u1*u3 - u2,{u0,u1,u2,u3});
- torder(trinksvars,lex)$
- gsort trinkspolys;
-
- gspoly(first trinkspolys,second trinkspolys);
- gvars trinkspolys;
- % Tagged basis and reduction trace. A tagged basis is a basis where
- % each polynomial is equated to a linear combination of the input
- % set. A tagged reduction shows how the result is computed by using
- % the basis polynomials.
- % First example for tagged polynomials: show how a polynomial is
- % represented as linear combination of the basis polynomials.
- % First I set up an environment for the computation.
- torder(trinksvars,lex)$
- % Then I compute an ordinary Groebner basis.
- bas:=groebner trinkspolys$
- % Next I assign a tag to each basis polynomial.
- taggedbas:=for i:=1:length bas collect mkid(p,i)=part(bas,i);
- % And finally I reduce a (tagged) polynomial wrt the tagged basis.
- preducet(new=w*p + 2*z*t - 11*b**3,taggedbas);
- % Second example for tagged polynomials: representing a Groebner basis
- % as a combination of the input polynomials, here in a simple geometric
- % problem.
- torder({x,y},lex)$
- groebnert {circle=x**2 + y**2 - r**2,line=a*x + b*y};
- % In the third example I enter two polynomials that have no common zero.
- % Consequently the basis is {1}. The tagged computation gives me a proof
- % for the inconsistency of the system which is independent of the
- % Groebner formalism.
- groebnert {circle1=x**2 + y**2 - 10,circle2=x**2 + y**2 - 2};
- % Solve a special elimination task by using a blockwise elimination
- % order defined by a matrix. The equation set goes back to A.M.H.
- % Levelt (Nijmegen). The question is whether there is a member in the
- % ideal which depends only on two variables. Here we select x4 and y1.
- % The existence of such a polynomial proves that the system has exactly
- % one degree of freedom.
- % The first two rows of the term order matrix define the groupwise
- % elimination. The remaining lines define a secondary local
- % lexicographical behavior which is needed to construct an admissible
- % ordering.
- f1:=y1^2 + z1^2 -1;
- f2:=x2^2 + y2^2 + z2^2 -1;
- f3:=x3^2 + y3^2 + z3^2 -1;
- f4:=x4^2 + z4^2 -1;
- f5:=y1*y2 + z1*z2;
- f6:=x2*x3 + y2*y3 + z2*z3;
- f7:=x3*x4 + z3*z4;
- f8:=x2 + x3 + x4 + 1;
- f9:=y1 + y2 + y3 - 1;
- f10:=z1 + z2 + z3 + z4;
- eqns:={f1,f2,f3,f4,f5,f6,f7,f8,f9,f10}$
- vars:={x2,x3,y2,y3,z1,z2,z3,z4,x4,y1}$
- torder(vars,matrix,
- mat((1,1,1,1,1,1,1,1,0,0),
- (0,0,0,0,0,0,0,0,1,1),
- (1,0,0,0,0,0,0,0,0,0),
- (0,1,0,0,0,0,0,0,0,0),
- (0,0,1,0,0,0,0,0,0,0),
- (0,0,0,1,0,0,0,0,0,0),
- (0,0,0,0,1,0,0,0,0,0),
- (0,0,0,0,0,1,0,0,0,0),
- (0,0,0,0,0,0,1,0,0,0),
- (0,0,0,0,0,0,0,0,1,0)));
- first reverse groebner(eqns,vars);
- % For a faster execution we convert the matrix into a
- % proper machine code routine.
- on comp;
- torder_compile(levelt,mat(
- (1,1,1,1,1,1,1,1,0,0),
- (0,0,0,0,0,0,0,0,1,1),
- (1,0,0,0,0,0,0,0,0,0),
- (0,1,0,0,0,0,0,0,0,0),
- (0,0,1,0,0,0,0,0,0,0),
- (0,0,0,1,0,0,0,0,0,0),
- (0,0,0,0,1,0,0,0,0,0),
- (0,0,0,0,0,1,0,0,0,0),
- (0,0,0,0,0,0,1,0,0,0),
- (0,0,0,0,0,0,0,0,1,0)));
- torder(vars,levelt)$
- first reverse groebner(eqns,vars);
- % For a homogeneous polynomial set we compute a graded Groebner
- % basis with grade limits. We use the graded term order with lex
- % as following order. As the grade vector has no zeros, this ordering
- % is functionally equivalent to a weighted ordering.
- torder({x,y,z},graded,{1,1,2},lex);
- dd_groebner(0,10,{x^10*y + y*z^5, x*y^12 + y*z^6});
- dd_groebner(0,50,{x^10*y + y*z^5, x*y^12 + y*z^6});
- dd_groebner(0,infinity,{x^10*y + y*z^5, x*y^12 + y*z^6});
- % Test groebner_walk
- trinkspolys := {45*p + 35*s - 165*b - 36,
- 35*p + 40*z + 25*t - 27*s,
- 15*w + 25*p*s + 30*z - 18*t - 165*b**2,
- - 9*w + 15*p*t + 20*z*s,
- w*p + 2*z*t - 11*b**3,
- 99*w - 11*s*b + 3*b**2,
- b**2 + 33/50*b + 2673/10000}$
- trinksvars := {w,p,z,t,s,b}$
- torder(trinksvars,gradlex)$
- gg:=groebner trinkspolys$
- g:=groebner_walk gg$
- on div$
- g;
- on varopt;
- g1:=solve({first g},{b});
- g0:=sub({first g1},g);
- solve({ second g0},{w});
- solve({third g0},{p});
- solve({part(g0,4)},{z});
- solve({part(g0,5)},{t});
- solve({part(g0,6)},{s});
- g0:=sub({second g1},g);
- solve({second g0},{w});
- solve({third g0},{p});
- solve({part(g0,4)},{z});
- solve({part(g0,5)},{t});
- solve({part(g0,6)},{s});
- % Example after the book "David Cox, John Little, Donal O'Shea:
- % "Ideals, Varieties and Algorithms", chapter 2, paragraph 8, example 3.
- % This example was given by Shigetoshi Katsura (Japan).
-
- off groebopt;torder({x,y,z,l},lex);
- g:=groebner{3*x^2+2*y*z-2*x*l,2*x*z-2*y*l,2*x*y-2*z-2*z*l,x^2+y^2+z^2-1}$
- gdimension g;
- gindependent_sets g;
- clear g, gg, trinkspolys, trinksvars$
- end;
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