123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233234235236237238239240241242243244245246247248249250251252253254255256257258259260261262263264265266267268269270271272273274275276277278279280281282283284285286287288289290291292293294295296297 |
- COMMENT
- REDUCE INTERACTIVE LESSON NUMBER 1
- David R. Stoutemyer
- University of Hawaii
- COMMENT This is lesson 1 of 7 interactive lessons about the REDUCE
- system for computer symbolic mathematics. These lessons presume an
- acquaintance with elementary calculus, together with a previous
- exposure to some computer programming language.
- These lessons have been designed for use on a DEC system 10 or 20.
- Apart from changes to the prompt and interrupt characters however
- they should work just as well with any REDUCE implementation.
- In REDUCE, any sequence of characters from the word "COMMENT" through
- the next semicolon or dollar-sign statement separator is an
- explanatory remark ignored by the system. In general, either
- separator signals the end of a statement, with the dollar sign
- suppressing any output that might otherwise automatically be produced
- by the statement. The typing of a carriage return initiates the
- immediate sequential execution of all statements which have been
- terminated on that line. When REDUCE is ready for more input, it will
- prompt you with an asterisk at the left margin.
- To terminate the lesson and return to the operating system, type an
- interrupt character (DEC: control-C ) at any time.
- Expressions can be formed using "**", "*", "/", "+", and "-" to
- indicate exponentiation, multiplication, division, addition, and
- subtraction or negation respectively. Assignments to variables can
- be done using the operator ":=". For example:;
- R2D2 := (987654321/15)**3;
- COMMENT The immediately preceding line, without a semicolon, is the
- computed output generated by the line with a semicolon which precedes
- it. Note that exact indefinite-precision rational arithmetic was
- used, in contrast to the limited-precision arithmetic of traditional
- programming languages.
- We can use the name R2D2 to represent its value in subsequent
- expressions such as;
- R2D2 := -R2D2/25 + 3*(13-5);
- COMMENT Now I will give you an opportunity to try some analogous
- computations. To do so, type the letter N followed by a carriage return
- in response to our question "CONT?" (You could type Y if you wish to
- relinquish this opportunity, but I strongly recommend reinforced
- learning through active participation.) After trying an example or two,
- type the command "CONT" terminated by a semicolon and carriage return
- when you wish to proceed with the rest of the lesson. To avoid
- interference with our examples, please don't assign anything to any
- variable names beginning with the letters E through I. To avoid lengthy
- delays, I recommend keeping all of your examples approximately as
- trivial as ours, saving your more ambitious experiments until after the
- lesson. If you happen to initiate a calculation requiring an undue
- amount of time to evaluate or to print, you can abort that computation
- with an interrupt to get back to the operating system. Restart REDUCE,
- followed by the statement "IN LESS1", followed by a semicolon and
- return, to restart the lesson at the beginning;
- PAUSE;
- COMMENT Now watch this example illustrating some more dramatic
- differences from traditional scientific programming systems:;
- E1 := 2*G + 3*G + H**3/H;
- COMMENT Note how we are allowed to use variables to which we have
- assigned no values! Note too how similar terms and similar factors
- are combined automatically. REDUCE also automatically expands
- products and powers of sums, together with placing expressions over
- common denominators, as illustrated by the examples:;
- E2 := E1*(F+G);
- E2 := E1**2;
- E1+1/E1;
- COMMENT Our last example also illustrates that there is no need to
- assign an expression if we do not plan to use its value later. Try
- some similar examples:;
- PAUSE;
- COMMENT It is not always desirable to expand expressions over a
- common denominator, and we can use the OFF statement to turn off
- either or both computational switches which control these
- transformations. The switch named EXP controls EXPansion, and the
- switch named MCD controls the Making of Common Denominators;
- OFF EXP, MCD;
- E2 := E1**2 $
- E2 := E2*(F+G) + 1/E1;
- COMMENT To turn these switches back on, we type:;
- ON EXP, MCD;
- COMMENT Try a few relevant examples with these switches turned off
- individually and jointly;
- PAUSE;
- ON EXP; % Just in case you turned it off.
- COMMENT Now consider the example:;
- E2 := (2*(F*H)**2 - F**2*G*H - (F*G)**2 - F*H**3 + F*H*G**2 - H**4
- + G*H**3)/(F**2*H - F**2*G - F*H**2 + 2*F*G*H - F*G**2
- - G*H**2 + G**2*H);
- COMMENT It is not obvious, but the numerator and denominator of this
- expression share a nontrivial common divisor which can be canceled.
- To make REDUCE automatically cancel greatest common divisors, we turn
- on the computational switch named GCD:;
- ON GCD;
- E2;
- COMMENT The switch is not on by default because
- 1. It can consume a lot of time.
- 2. Often we know in advance the few places where a nontrivial
- GCD can occur in our problem.
- 3. Even without GCD cancellation, expansion and common denomin-
- ators guarantee that any rational expression which is equiv-
- alent to zero simplifies to zero.
- 4. When the denominator is the greatest common divisor, such
- as for (X**2 - 2*X + 1)/(X-1), REDUCE cancels the
- greatest common divisor even when GCD is OFF.
- 5. GCD cancellation sometimes makes expressions more
- complicated, such as with (F**10 - G**10)/(F**2 - F*G).
- Try the examples mentioned in this comment, together with one
- or two other relevant ones;
- PAUSE;
- COMMENT Exact rational arithmetic can consume an alarming amount of
- computer time when the constituent integers have quite large
- magnitudes, and the results become awkward to interpret
- qualitatively. When this is the case and somewhat inexact numerical
- coefficients are acceptable, we can have the arithmetic done floating
- point by turning on the computational switch ROUNDED. With this switch
- on, any non-integer rational numbers are approximated by floating-point
- numbers, and the result of any arithmetic operation is floating-point
- when any of its operands is floating point. For example:;
- ON ROUNDED;
- E1:= (12.3456789E3 *F + 3*G)**2 + 1/2;
- COMMENT With ROUNDED off, any floating-point constants are
- automatically approximated by rational numbers:;
- OFF FLOAT;
- E1 := 12.35*G;
- PAUSE;
- COMMENT A number of elementary functions, such as SIN, COS and LOG,
- are built into REDUCE. Moreover, the letter E represents the base of
- the natural logarithms, so the exponentiation operator enables us to
- represent the exponential function as well as fractional powers. For
- example:;
- E1:= SIN(-F*G) + LOG(E) + (3*G**2*COS(-1))**(1/2);
- COMMENT What automatic simplifications can you identify in this
- example?
- Note that most REDUCE implementations do not approximate the values
- of these functions for non-trivial numerical arguments, and exact
- computations are generally impossible for such cases.
- Experimentally determine some other built-in simplifications for
- these functions;
- PAUSE;
- COMMENT Later you will learn how to introduce additional
- simplifications and additional functions, including numerical
- approximations for examples such as COS(1).
- Differentiation is also built-into REDUCE. For example, to
- differentiate E1 with respect to F;
- E2 := DF(E1,F);
- COMMENT To compute the second derivative of E2 with respect to G, we
- can type either DF(E2,G,2) or DF(E1,F,1,G,2) or DF(E1,F,G,2) or
- DF(E1,G,2,F,1) or;
- DF(E1,G,2,F);
- COMMENT Surely you can't resist trying a few derivatives of your
- own! (Careful, High-order derivatives can be alarmingly complicated);
- PAUSE;
- COMMENT REDUCE uses the name I to represent (-1)**(1/2),
- incorporating some simplification rules such as replacing I**2 by -1.
- Here is an opportunity to experimentally determine other
- simplifications such as for I**3, 1/I**23, and (I**2-1)/(I-1);
- PAUSE;
- COMMENT Clearly it is inadvisable to use E or I as a variable. T is
- also inadvisable for reasons that will become clear later.
- The value of a variable is said to be "bound" to the variable. Any
- variable to which we have assigned a value is called a bound variable,
- and any variable to which we have not assigned a value is called an
- indeterminate. Occasionally it is desirable to make a bound variable
- into an indeterminate, and this can be done using the CLEAR command.
- For example:;
- CLEAR R2D2, E1, E2;
- E2;
- COMMENT If you suspect that a degenerate assignment, such as E1:=E1,
- would suffice to clear a bound variable, try it on one of your own
- bound variables:;
- PAUSE;
- COMMENT REDUCE also supports matrix algebra, as illustrated by the
- following sequence:;
- MATRIX E1(4,1), F, H;
- COMMENT This declaration establishes E1 as a matrix with 4 rows and 1
- column, while establishing F and H as matrices of unspecified size.
- To establish element values (and sizes if not already established in
- the MATRIX declaration), we can use the MAT function, as illustrated
- by the following example:;
- H := MAT((LOG(G), G+3), (G, 5/7));
- COMMENT Only after establishing the size and establishing the element
- values of a declared matrix by executing a matrix assignment can we
- refer to an individual element or to the matrix as a whole. For
- example to increase the last element of H by 1 then form twice the
- transpose of H, we can type;
- H(2,2) := H(2,2) + 1;
- 2*TP(H);
- COMMENT To compute the determinant of H:;
- DET(H);
- COMMENT To compute the trace of H:;
- TRACE(H);
- COMMENT To compute the inverse of H, we can type H**(-1) or 1/H. To
- compute the solution to the equation H*F = MAT((G),(2)), we can
- left-multiply the right-hand side by the inverse of H:;
- F := 1/H*MAT((G),(2));
- COMMENT Notes:
- 1. MAT((G),(2))/H would denote right-multiplication by the
- inverse, which is not what we want.
- 2. Solutions for a set of right-hand-side vectors are most
- efficiently computed simultaneously by collecting the right-
- hand sides together as the columns of a single multiple-column
- matrix.
- 3. Subexpressions of the form 1/H*... or H**(-1)*... are computed
- more efficiently than if the inverse is computed separately in
- a previous statement, so separate computation of the inverse
- is advisable only if several solutions are desired and if
- they cannot be computed simultaneously.
- 4. MAT must have parentheses around each row of elements even if
- there is only one row or only one element per row.
- 5. References to individual matrix elements must have exactly two
- subscripts, even if the matrix has only one row or one column.
- Congratulations on completing lesson 1! I urge you to try a sequence of
- more ambitious examples for the various features that have been
- introduced, in order to gain some familiarity with the relationship
- between problem size and computing time for various operations. (In most
- implementations, the command "ON TIME" causes computing time to be
- printed.) I also urge you to bring to the next lesson appropriate
- examples from textbooks, articles, or elsewhere, in order to experience
- the decisive learning reinforcement afforded by meaningful personal
- examples that are not arbitrarily contrived.
- To avoid the possibility of interference from assignments and declar-
- ations in lesson 1, it is wise to execute lesson 2 in a fresh REDUCE
- job, when you are ready.
- ;END;
|