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- A brief CRC tutorial.
- A CRC is a long-division remainder. You add the CRC to the message,
- and the whole thing (message+CRC) is a multiple of the given
- CRC polynomial. To check the CRC, you can either check that the
- CRC matches the recomputed value, *or* you can check that the
- remainder computed on the message+CRC is 0. This latter approach
- is used by a lot of hardware implementations, and is why so many
- protocols put the end-of-frame flag after the CRC.
- It's actually the same long division you learned in school, except that
- - We're working in binary, so the digits are only 0 and 1, and
- - When dividing polynomials, there are no carries. Rather than add and
- subtract, we just xor. Thus, we tend to get a bit sloppy about
- the difference between adding and subtracting.
- Like all division, the remainder is always smaller than the divisor.
- To produce a 32-bit CRC, the divisor is actually a 33-bit CRC polynomial.
- Since it's 33 bits long, bit 32 is always going to be set, so usually the
- CRC is written in hex with the most significant bit omitted. (If you're
- familiar with the IEEE 754 floating-point format, it's the same idea.)
- Note that a CRC is computed over a string of *bits*, so you have
- to decide on the endianness of the bits within each byte. To get
- the best error-detecting properties, this should correspond to the
- order they're actually sent. For example, standard RS-232 serial is
- little-endian; the most significant bit (sometimes used for parity)
- is sent last. And when appending a CRC word to a message, you should
- do it in the right order, matching the endianness.
- Just like with ordinary division, you proceed one digit (bit) at a time.
- Each step of the division you take one more digit (bit) of the dividend
- and append it to the current remainder. Then you figure out the
- appropriate multiple of the divisor to subtract to being the remainder
- back into range. In binary, this is easy - it has to be either 0 or 1,
- and to make the XOR cancel, it's just a copy of bit 32 of the remainder.
- When computing a CRC, we don't care about the quotient, so we can
- throw the quotient bit away, but subtract the appropriate multiple of
- the polynomial from the remainder and we're back to where we started,
- ready to process the next bit.
- A big-endian CRC written this way would be coded like:
- for (i = 0; i < input_bits; i++) {
- multiple = remainder & 0x80000000 ? CRCPOLY : 0;
- remainder = (remainder << 1 | next_input_bit()) ^ multiple;
- }
- Notice how, to get at bit 32 of the shifted remainder, we look
- at bit 31 of the remainder *before* shifting it.
- But also notice how the next_input_bit() bits we're shifting into
- the remainder don't actually affect any decision-making until
- 32 bits later. Thus, the first 32 cycles of this are pretty boring.
- Also, to add the CRC to a message, we need a 32-bit-long hole for it at
- the end, so we have to add 32 extra cycles shifting in zeros at the
- end of every message,
- These details lead to a standard trick: rearrange merging in the
- next_input_bit() until the moment it's needed. Then the first 32 cycles
- can be precomputed, and merging in the final 32 zero bits to make room
- for the CRC can be skipped entirely. This changes the code to:
- for (i = 0; i < input_bits; i++) {
- remainder ^= next_input_bit() << 31;
- multiple = (remainder & 0x80000000) ? CRCPOLY : 0;
- remainder = (remainder << 1) ^ multiple;
- }
- With this optimization, the little-endian code is particularly simple:
- for (i = 0; i < input_bits; i++) {
- remainder ^= next_input_bit();
- multiple = (remainder & 1) ? CRCPOLY : 0;
- remainder = (remainder >> 1) ^ multiple;
- }
- The most significant coefficient of the remainder polynomial is stored
- in the least significant bit of the binary "remainder" variable.
- The other details of endianness have been hidden in CRCPOLY (which must
- be bit-reversed) and next_input_bit().
- As long as next_input_bit is returning the bits in a sensible order, we don't
- *have* to wait until the last possible moment to merge in additional bits.
- We can do it 8 bits at a time rather than 1 bit at a time:
- for (i = 0; i < input_bytes; i++) {
- remainder ^= next_input_byte() << 24;
- for (j = 0; j < 8; j++) {
- multiple = (remainder & 0x80000000) ? CRCPOLY : 0;
- remainder = (remainder << 1) ^ multiple;
- }
- }
- Or in little-endian:
- for (i = 0; i < input_bytes; i++) {
- remainder ^= next_input_byte();
- for (j = 0; j < 8; j++) {
- multiple = (remainder & 1) ? CRCPOLY : 0;
- remainder = (remainder >> 1) ^ multiple;
- }
- }
- If the input is a multiple of 32 bits, you can even XOR in a 32-bit
- word at a time and increase the inner loop count to 32.
- You can also mix and match the two loop styles, for example doing the
- bulk of a message byte-at-a-time and adding bit-at-a-time processing
- for any fractional bytes at the end.
- To reduce the number of conditional branches, software commonly uses
- the byte-at-a-time table method, popularized by Dilip V. Sarwate,
- "Computation of Cyclic Redundancy Checks via Table Look-Up", Comm. ACM
- v.31 no.8 (August 1998) p. 1008-1013.
- Here, rather than just shifting one bit of the remainder to decide
- in the correct multiple to subtract, we can shift a byte at a time.
- This produces a 40-bit (rather than a 33-bit) intermediate remainder,
- and the correct multiple of the polynomial to subtract is found using
- a 256-entry lookup table indexed by the high 8 bits.
- (The table entries are simply the CRC-32 of the given one-byte messages.)
- When space is more constrained, smaller tables can be used, e.g. two
- 4-bit shifts followed by a lookup in a 16-entry table.
- It is not practical to process much more than 8 bits at a time using this
- technique, because tables larger than 256 entries use too much memory and,
- more importantly, too much of the L1 cache.
- To get higher software performance, a "slicing" technique can be used.
- See "High Octane CRC Generation with the Intel Slicing-by-8 Algorithm",
- ftp://download.intel.com/technology/comms/perfnet/download/slicing-by-8.pdf
- This does not change the number of table lookups, but does increase
- the parallelism. With the classic Sarwate algorithm, each table lookup
- must be completed before the index of the next can be computed.
- A "slicing by 2" technique would shift the remainder 16 bits at a time,
- producing a 48-bit intermediate remainder. Rather than doing a single
- lookup in a 65536-entry table, the two high bytes are looked up in
- two different 256-entry tables. Each contains the remainder required
- to cancel out the corresponding byte. The tables are different because the
- polynomials to cancel are different. One has non-zero coefficients from
- x^32 to x^39, while the other goes from x^40 to x^47.
- Since modern processors can handle many parallel memory operations, this
- takes barely longer than a single table look-up and thus performs almost
- twice as fast as the basic Sarwate algorithm.
- This can be extended to "slicing by 4" using 4 256-entry tables.
- Each step, 32 bits of data is fetched, XORed with the CRC, and the result
- broken into bytes and looked up in the tables. Because the 32-bit shift
- leaves the low-order bits of the intermediate remainder zero, the
- final CRC is simply the XOR of the 4 table look-ups.
- But this still enforces sequential execution: a second group of table
- look-ups cannot begin until the previous groups 4 table look-ups have all
- been completed. Thus, the processor's load/store unit is sometimes idle.
- To make maximum use of the processor, "slicing by 8" performs 8 look-ups
- in parallel. Each step, the 32-bit CRC is shifted 64 bits and XORed
- with 64 bits of input data. What is important to note is that 4 of
- those 8 bytes are simply copies of the input data; they do not depend
- on the previous CRC at all. Thus, those 4 table look-ups may commence
- immediately, without waiting for the previous loop iteration.
- By always having 4 loads in flight, a modern superscalar processor can
- be kept busy and make full use of its L1 cache.
- Two more details about CRC implementation in the real world:
- Normally, appending zero bits to a message which is already a multiple
- of a polynomial produces a larger multiple of that polynomial. Thus,
- a basic CRC will not detect appended zero bits (or bytes). To enable
- a CRC to detect this condition, it's common to invert the CRC before
- appending it. This makes the remainder of the message+crc come out not
- as zero, but some fixed non-zero value. (The CRC of the inversion
- pattern, 0xffffffff.)
- The same problem applies to zero bits prepended to the message, and a
- similar solution is used. Instead of starting the CRC computation with
- a remainder of 0, an initial remainder of all ones is used. As long as
- you start the same way on decoding, it doesn't make a difference.
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