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- # This example simulates a `swinging Atwood's machine'. An Atwood's
- # machine consists of two masses joined by a taut length of cord. The cord
- # is suspended from a pulley. The heavier mass (M) would normally win
- # against the lighter mass (m), and pull it upward. A `swinging' Atwood's
- # machine is an Atwood's machine with an additional degree of freedom: it
- # allows the lighter mass to swing back and forth in a plane, at the same
- # time as it is being drawn upward.
- # Let `a' denote the angle by which the cord extending to the lighter mass
- # deviates from the vertical. Let `l' denote the distance along the cord
- # between the pulley and the lighter mass. Then the system of differential
- # equations below will describe the evolution of the system.
- # You may run this example, with output to an X window in real time, by doing
- #
- # ode < atwoods.ode | graph -T X -x 9 11 -y -1 1 -m 0 -S 1
- #
- # The plot will trace out `l' and `ldot' (its time derivative). The `-m 0
- # -S 1' option requests that successive datapoints not be joined by line
- # segments, but rather that marker symbol #1 (a point) be plotted at the
- # location of each datapoint.
- # You may have some difficulty believing the results of this simulation.
- # Allowing the lighter mass to swing, it turns out, may prevent the heavier
- # mass from winning against it. The system may oscillate,
- # non-periodically.
- m = 1 # lighter mass
- M = 1.0625 # heavier mass
- a = 0.5 # initial angle of cord from vertical, in radians
- adot = 0
- l = 10 # initial distance along cord from pulley to mass m
- ldot = 0
- g = 9.8 # acceleration due to gravity
- ldot' = ( m * l * adot * adot - M * g + m * g * cos(a) ) / (m + M)
- l' = ldot
- adot' = (-1/l) * (g * sin(a) + 2 * adot * ldot)
- a' = adot
- print l, ldot
- step 0, 400
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