GrauKatze 05f70669c9 Сконфигурирована и подготовлена база для проекта | 2 years ago | |
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LICENSE | 2 years ago | |
README.md | 2 years ago | |
once.js | 2 years ago | |
package.json | 2 years ago |
Only call a function once.
var once = require('once')
function load (file, cb) {
cb = once(cb)
loader.load('file')
loader.once('load', cb)
loader.once('error', cb)
}
Or add to the Function.prototype in a responsible way:
// only has to be done once
require('once').proto()
function load (file, cb) {
cb = cb.once()
loader.load('file')
loader.once('load', cb)
loader.once('error', cb)
}
Ironically, the prototype feature makes this module twice as complicated as necessary.
To check whether you function has been called, use fn.called
. Once the
function is called for the first time the return value of the original
function is saved in fn.value
and subsequent calls will continue to
return this value.
var once = require('once')
function load (cb) {
cb = once(cb)
var stream = createStream()
stream.once('data', cb)
stream.once('end', function () {
if (!cb.called) cb(new Error('not found'))
})
}
once.strict(func)
Throw an error if the function is called twice.
Some functions are expected to be called only once. Using once
for them would
potentially hide logical errors.
In the example below, the greet
function has to call the callback only once:
function greet (name, cb) {
// return is missing from the if statement
// when no name is passed, the callback is called twice
if (!name) cb('Hello anonymous')
cb('Hello ' + name)
}
function log (msg) {
console.log(msg)
}
// this will print 'Hello anonymous' but the logical error will be missed
greet(null, once(msg))
// once.strict will print 'Hello anonymous' and throw an error when the callback will be called the second time
greet(null, once.strict(msg))